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Toolkit运行VASP任务，为什么概率性运行失败？ Intel oneAPI Toolkit（Intel并行计算平台）运行的VASP（用于电子结构计算和量子力学-分子动力学模拟）任务对CPU硬件版本有深度依赖，在小规格Pod场景下概率性运行失败，建议切换oneAPI版本或使用4核以上Pod运行。 父主题： 容器工作负载类
{ "containerPort": 2222, "name": "tfjob-port"
{ "containerPort": 80 } ]
that generate Endpoints and EndpointSlice resources for Services interpret this to mean that all endpoints are considered "ready" even if the
授权项分类 表1 Namespace 权限 对应API接口 授权项 IAM项目(Project) 企业项目(Enterprise Project) 创建Namespace POST /api/v1/namespaces CCI:namespace:create √ √ 查询namespace
"${SCRIPT_ROOT}"/hack/boilerplate.go.txt # To use your own boilerplate text append: # --go-header-file "${SCRIPT_ROOT}"/hack/custom-boilerplate.go.txt boilerplate
incoming requests are matched. pathType 否 String PathType determines the interpretation of the Path matching. PathType can be one of the following values:
7.22 imagePullPolicy: Always ports: - containerPort: 3306 resources: limits: memory: "500Mi"
{ "containerPort": 2222, "name": "tfjob-port"
{ "containerPort": 2222, "name": "tfjob-port"
kind: Namespace metadata: name: namespace-test labels: sys_enterprise_project_id: "0" annotations: namespace.kubernetes.io/flavor:
kind: Namespace metadata: name: namespace-test labels: sys_enterprise_project_id: "0" annotations: namespace.kubernetes.io/flavor:
{ "containerPort": 2222, "name": "tfjob-port"
{ "containerPort": 2222, "name": "tfjob-port"
that generate Endpoints and EndpointSlice resources for Services interpret this to mean that all endpoints are considered "ready" even if the
{ "containerPort": 2222, "name": "tfjob-port"
that generate Endpoints and EndpointSlice resources for Services interpret this to mean that all endpoints are considered "ready" even if the
"name" : "mpimaster", "ports" : [ { "containerPort" : 22, "name" : "mpijob-port" } ],
that generate Endpoints and EndpointSlice resources for Services interpret this to mean that all endpoints are considered "ready" even if the
that generate Endpoints and EndpointSlice resources for Services interpret this to mean that all endpoints are considered "ready" even if the
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